High School Maths Examples and Questions

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Answers − Solving Equations, Multiplication and Division 1

1.   If 7 y = 21, what is the value of y?

  The inverse of × 7 is ÷ 7. So divide both sides by 7

  
  7y= 21
÷7 =÷7
  
  
     y=    3

  To verify, put the value of y = 3 back into the original equation
   7 × 3 = 21

2.   If 5 a = 55, what is the value of a?

  The inverse of × 5 is ÷ 5. So divide both sides by 5

  
  5a= 55
÷5 =÷5
  
  
     a=   11

  To check, put the value of a = 11 back into the original equation
   5 × 11 = 55

3.   If 6 z = 42, solve z

  The inverse of × 6 is ÷ 6. So divide both sides by 6

  
  6z= 42
÷6 =÷6
  
  
     z=   7

  To verify, put the value of z = 7 back into the original equation
   6 × 7 = 42

4.   If 9 y = 36, what is the value of y?

  The inverse of × 9 is ÷ 9. So divide both sides by 9

  
  9y= 36
÷9 =÷9
  
  
    y=    4

  To check, put the value of y = 4 back into the original equation
   9 × 4 = 36

5.   If 8 z = 24, solve z

  The inverse of × 8 is ÷ 8. So divide both sides by 8

  
  8z= 24
÷8 =÷8
  
  
    z=    3

  To verify, put the value of z = 3 back into the original equation
   8 × 3 = 24

6.   If y/8 = 5, what is the value of y?

  The inverse of ÷ 8 is × 8. So multiply both sides by 8

  
  y/8= 5
×8=×8
  
  
     y= 40

  To check, put the value of y = 40 back into the original equation
   40 ÷ 8 = 5

7.   If b/8 = 7, solve b

  The inverse of ÷ 8 is × 8. So multiply both sides by 8

  
  b/8= 7
×8=×8
  
  
     b= 56

  To verify, put the value of b = 56 back into the original equation
   56 ÷ 8 = 7

8.   If y/9 = 6, what is the value of y?

  The inverse of ÷ 9 is × 9. So multiply both sides by 9

  
  y/9= 6
×9=×9
  
  
     y= 54

  To check, put the value of y = 54 back into the original equation
   54 ÷ 9 = 6

9.   If z/4 = 9, solve z

  The inverse of ÷ 4 is × 4. So multiply both sides by 4

  
  z/4= 9
×4=×4
  
  
     z= 36

  To verify, put the value of z = 36 back into the original equation
   36 ÷ 4 = 9

10.   If b/3 = 25, what is the value of b?

  The inverse of ÷ 3 is × 3. So multiply both sides by 3

  
  b/3= 25
×3=×3
  
  
     b=  75

  To check, put the value of b = 75 back into the original equation
   75 ÷ 3 = 25


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